hare

[hare] The Hare programming language
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util.ha (1834B)


      1 // SPDX-License-Identifier: MPL-2.0
      2 // (c) Hare authors <https://harelang.org>
      3 
      4 // The following code was initially ported from BearSSL.
      5 //
      6 // Copyright (c) 2017 Thomas Pornin <pornin@bolet.org>
      7 //
      8 // Permission is hereby granted, free of charge, to any person obtaining a copy
      9 // of this software and associated documentation files (the "Software"), to deal
     10 // in the Software without restriction, including without limitation the rights
     11 // to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
     12 // copies of the Software, and to permit persons to whom the Software is
     13 // furnished to do so, subject to the following conditions:
     14 //
     15 // The above copyright notice and this permission notice shall be included in
     16 // all copies or substantial portions of the Software.
     17 //
     18 // THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
     19 // IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
     20 // FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
     21 // AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
     22 // LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
     23 // OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
     24 // SOFTWARE.
     25 use bytes;
     26 
     27 // Sets encoded bitlen of 'x' to 'ebitlen' and then zeroes its effective words.
     28 export fn zero(x: []word, ebitlen: word) void = {
     29 	x[0] = ebitlen;
     30 	const ewordlen = ewordlen(x);
     31 	bytes::zero((x: *[*]u8)[size(word)..(1 + ewordlen) * size(word)]);
     32 };
     33 
     34 // Checks whether the effective words of 'x' are zero. Returns 1 if so, or 0
     35 // otherwise.
     36 export fn iszero(x: []word) u32 = {
     37 	let z: u32 = 0;
     38 
     39 	for (let i = ewordlen(x); i > 0; i -= 1) {
     40 		z |= x[i];
     41 	};
     42 	return ~(z | -(z: i32): u32) >> 31;
     43 };
     44 
     45 fn isodd(x: []word) bool = {
     46 	return x[1] & 1 == 1;
     47 };